document.write( "Question 655140: what qualntity of a 65% acid solution must be mixed with a 35% solution to produce 300 mL of a 60% solution?\r
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Algebra.Com's Answer #408953 by checkley79(3341)\"\" \"About 
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.65X+.35(300-X)=300*.60
\n" ); document.write( ".65X+105-.35X=180
\n" ); document.write( ".30X=180-105
\n" ); document.write( ".30X=75
\n" ); document.write( "X=75/.30
\n" ); document.write( "X=250 mL OF .65% ACID IS USED.
\n" ); document.write( "300-250=50 mL OF .35% ACID IS USED.
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