document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=655130>Question 655130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many litres of a 90% acid solution must be mixed with a 25% acid solution to get 250 Litres of a 80% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408943 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .90x+.25(250-x)=250*.80<BR>\n" );
document.write( ".90x+62.5-.25x=200<BR>\n" );
document.write( ".65x=200-62.5<BR>\n" );
document.write( ".65x=137.5<BR>\n" );
document.write( "x=137.5/.65<BR>\n" );
document.write( "x=211.54 liters of 90% acid.<BR>\n" );
document.write( "250-211.54=38.46 liters of 25% acid.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".90*211.54+.25*38.46=250*.80<BR>\n" );
document.write( "190.386+9.615=200<BR>\n" );
document.write( "200=200 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );