document.write( "Question 655116: I just need someone to review my work.
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\n" ); document.write( "If the cholesterol level of men in the community is normally distributed with a mean of 200 and a standard deviation of 25, what is the probability that a randomly selected sample of of 49 men will have a mean between 190 and 205? (hint: this question pertains to the sampling distribution of the mean).\r
\n" ); document.write( "\n" ); document.write( "(190-200)/(25/√49)= -10/3.57= -2.80
\n" ); document.write( "(205-200)/(25//√49)= 5/3.57= 1.4\r
\n" ); document.write( "\n" ); document.write( "P(X-Bar > 190) = 0.50 –.4974= .0026\r
\n" ); document.write( "\n" ); document.write( "0.26% of sample means (from repeated samples of n=49 men) will have cholesterol mean value greater than 190.\r
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\n" ); document.write( "\n" ); document.write( "P(X-Bar <205) = 0.50 + .4192 = .9192\r
\n" ); document.write( "\n" ); document.write( "91.92% of sample means (from repeated samples of n=49) will have a cholesterol level less than 205.\r
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Algebra.Com's Answer #408941 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "RE TY, Yes, NORMSDIST(-2.8) is .00256  and NORMSDIST(1.4) is .91924
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document.write( " .91924
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document.write( "-.00256  is  .91668  Or = .9167   Or 91.67%
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document.write( "(Ans Correct, as listed, rounded to 4 decimal points, calculation  Using 5)
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document.write( "As to: .9192 - .0026 (Using 4 decimal points for calculation...)= 91.66% \r
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document.write( "t = (190-200)/(25/√49)= -10/3.57= -2.80 Yes
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document.write( "t =  (205-200)/(25//√49)= 5/3.57= 1.4   Yes
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document.write( "P(180< x    <205) = P( -2.80  ≤ t  ≤ 1.4) = .91924 - .00256 = .9167 \n" );
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