document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=654917>Question 654917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many liters of a 80% acid solution must be mixed with a 30% acid solution to get 300 liters of a 70% acid solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408882 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .80X+.30(300-X)=300*.70<BR>\n" );
document.write( ".80X+90-.30X=210<BR>\n" );
document.write( ".50X=210-90<BR>\n" );
document.write( ".50X=120<BR>\n" );
document.write( "X=120/.50<BR>\n" );
document.write( "X=240 LITERS OF 80% ARE USED.<BR>\n" );
document.write( "300-240=60 LITERS OF 30% ARE USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".80*240+.30*60=210<BR>\n" );
document.write( "192+18=210<BR>\n" );
document.write( "210=210 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );