document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=654865>Question 654865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for this problem i have to factor completely..  \r<BR>\n" );
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document.write( "x^3-8<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408859 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since x = 2 is a root (makes x^3-8 = 0), we can divide x^3-8 by (x-2) to get (x^2 + 2*x + 4). The quadratic can be factored, but the roots are complex.<BR>\n" );
document.write( "x = {-1 +i[sqrt(3)], -1 - i[sqrt(3)]} </SPAN>\n" );
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