document.write( "Question 654638: How do i solve for A and B in the following equation. (B-2)+3A=42 \n" ); document.write( "
Algebra.Com's Answer #408816 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"%28B-2%29%2B3A=42\" first solve for \"A\"\r
\n" ); document.write( "\n" ); document.write( "\"3A=42-%28B-2%29\" \r
\n" ); document.write( "\n" ); document.write( "\"3A=42-B%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"3A=44-B\"\r
\n" ); document.write( "\n" ); document.write( "\"A=44%2F3-B%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28A=14.67-B%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"B-2%2B3A=42\" now solve for \"B\"\r
\n" ); document.write( "\n" ); document.write( "\"B=42%2B2-3A\" \r
\n" ); document.write( "\n" ); document.write( "\"B=highlight%2844-3A%29\"\r
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