document.write( "Question 654624: A 3-digit number when divided by 5 has an even quotient. When it is divided by 3, it also has an even quotient.\r
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Algebra.Com's Answer #408814 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "It has to be a multiple of 5.  All multiples of 5 either \r\n" );
document.write( "end in 0 or 5.  Since it has to be even it has to end in 0,\r\n" );
document.write( "since if it ended in 5 it would be odd.\r\n" );
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document.write( "Therefore the answer to this \r\n" );
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\n" ); document.write( "a. what is the digit in the ones place?
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document.write( "must be 0, because the digit on the right end of the number is the\r\n" );
document.write( "ones digit.\r\n" );
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\n" ); document.write( "b. what can the number be?
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document.write( "Since it ends with a zero it is divisible by 10. So if you divide \r\n" );
document.write( "it by 10, the quotient will be a 2-digit number which is the same \r\n" );
document.write( "as the number without the 0 on the right end.  \r\n" );
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document.write( "But the quotient will still be divisible by 3.   \r\n" );
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document.write( "So the number could be any two digit number that is a \r\n" );
document.write( "multiple of 3 with a 0 on the right end of it for its ones digit.  \r\n" );
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document.write( "The smallest 2-digit number that is a multiple of 3 is 12, so the \r\n" );
document.write( "smallest the number could be is 120.  \r\n" );
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document.write( "The largest 2-digit number that is a multiple of 3 is 99, so the \r\n" );
document.write( "largest the number could be is 990. \r\n" );
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document.write( "So it could be any of these thirty 3-digit numbers:\r\n" );
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document.write( "120, 150, 180, 210, 240, 270, 300, 330, 360, 390,\r\n" );
document.write( "420, 450, 480, 510, 540, 570, 600, 630, 660, 690,\r\n" );
document.write( "720, 750, 780, 810, 840, 870, 900, 930, 960, 990.\r\n" );
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document.write( "Edwin
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