document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=654610>Question 654610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help to find the equation to this senareo: Nancy has 60 feet of fencing to enclose a run for  her dog, Daisy. She wants the run to be as twice as long as it is wide. What dimensions should she use for the dog run? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408806 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=60<BR>\n" );
document.write( "L=2W<BR>\n" );
document.write( "2*2W+2W=60<BR>\n" );
document.write( "4W+2W=60<BR>\n" );
document.write( "6W=60<BR>\n" );
document.write( "W=60/6<BR>\n" );
document.write( "W=10 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*10<BR>\n" );
document.write( "L=20 ANS FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*20+2*10=60<BR>\n" );
document.write( "40+20=60<BR>\n" );
document.write( "60=60 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );