document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=654345>Question 654345</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that the weekly demand for Ford car sales follows a normal distribution with mean 50,000 cars and standard deviation 14,000 cars.\r<BR>\n" );
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document.write( "a) There is a 1% chance that Ford will sell more than what number of cars during the next year?\r<BR>\n" );
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document.write( "b) What is the probability that Ford will sell between 2.4 and 2.7 million cars during the next year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408779 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume that the weekly demand for Ford car sales follows a normal distribution with mean 50,000 cars and standard deviation 14,000 cars.<BR>\n" );
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document.write( "a) There is a 1% chance that Ford will sell more than what number of cars during the next year?<BR>\n" );
document.write( "Find the z-value with a left tail of 99%: z = 2.3263<BR>\n" );
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document.write( "Find the corresponding x(car sales number) using x = z*s+u<BR>\n" );
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document.write( "# of car sales = 2.3263*14000+50000 = 82569<BR>\n" );
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document.write( "b) What is the probability that Ford will sell between 2.4 and 2.7 million cars during the next year?<BR>\n" );
document.write( "Find the z-values for 2.4 mil and 2.7 mil ; then find the probability<BR>\n" );
document.write( "that lies between those z-values.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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