document.write( "Question 654524: I couldn't find the right category for my question. I'm working on conditional statements and biconditionals. For this statement I have to write it as its converse, which I did here.\r
\n" );
document.write( "\n" );
document.write( "If point B lies on (segment) AC, then AB + BC = AC.
\n" );
document.write( "Converse: If AB + BC = AC, then point B lies on (segment) AC.\r
\n" );
document.write( "\n" );
document.write( "Now I have to determine if this converse statement is true, and if it is, I have to write it as a biconditional.\r
\n" );
document.write( "\n" );
document.write( "But I don't know if it's true or not. I'm not very good at math when it's put into words and statements.\r
\n" );
document.write( "\n" );
document.write( "Thanks so much for your help! \n" );
document.write( "
Algebra.Com's Answer #408757 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "The converse is true, therefore, the biconditional is stated:\r\n" ); document.write( "\r\n" ); document.write( "point B lies on (segment) AC if and only if AB + BC = AC\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |