document.write( "Question 654518: I am really stuck on how to answer this question, it says solve the following equation.. $\"+e%5E%28x%29=2e%5E%281-2x%29+\"$ \r
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Algebra.Com's Answer #408754 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+e%5Ex\"$ = $\"2%2Ae%5E%281-2x%29+\"$
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document.write( "Divide both sides by \r\n" );
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document.write( " = \r\n" );
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document.write( "Subtract exponents of e on the left, cancel on the right:\r\n" );
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document.write( " = \r\n" );
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document.write( " = 2\r\n" );
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document.write( " = 2\r\n" );
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document.write( "Use the principle that equation  is equivalent to the\r\n" );
document.write( "equation A = ln(B) to rewrite the above as\r\n" );
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document.write( "3x - 1 = ln(2)\r\n" );
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document.write( "    3x = 1 + ln(2)\r\n" );
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document.write( "     x = \r\n" );
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document.write( "     x ≈ 0.5643823935\r\n" );
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document.write( "Edwin

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