document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=654364>Question 654364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose a basketball player is an excellent free throw shooter and makes 97% of his free throws  (i.e., he has a 97% chance of making a single free throw). Assume that free throw shots are<BR>\n" );
document.write( "independent of one another. Find the probability that the player will make three consecutive free<BR>\n" );
document.write( "throws.<BR>\n" );
document.write( "A) 0.9127 B) 0.0873 C) 1 D) 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408683 by </B><A HREF=/tutors/aboutme.mpl?userid=schmidtmomto6><B>schmidtmomto6(24)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=schmidtmomto6><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=schmidtmomto6><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You just take the chances of him making the first shot (.97) times his chances of making the 2nd shot (.97) times his chance of making te 3rd shot (.97).<BR>\n" );
document.write( ".97*.97*.97= .9127 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );