document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=654333>Question 654333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 30% copper should be mixed with 100 ounces of an alloy that is 80% copper in order to get an alloy that is 40% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408672 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408672\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 30% copper should be mixed with 100 ounces of an alloy that is 80% copper in order to get an alloy that is 40% copper?<BR>\n" );
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document.write( "let x=amt of 30% copper to be mixed<BR>\n" );
document.write( "x+100=amt of 40% copper alloy<BR>\n" );
document.write( "..<BR>\n" );
document.write( "30%x+80%*100=40%(x+100)<BR>\n" );
document.write( ".3x+80=.4x+40<BR>\n" );
document.write( ".x=40<BR>\n" );
document.write( "x=400<BR>\n" );
document.write( "amt of 30% copper to be mixed=400 ounces </SPAN>\n" );
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