document.write( "Question 654261: According to Chebyshevs theorem about 75% of a particular gym members aged between 19.4 and 76.6. Use this information to find the mean and standard deviation of the ages of the members of a gym. \n" ); document.write( "
Algebra.Com's Answer #408662 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! According to Chebyshevs theorem about 75% of a particular gym members aged between 19.4 and 76.6. Use this information to find the mean and standard deviation of the ages of the members of a gym. \n" ); document.write( "------ \n" ); document.write( "Solve: \n" ); document.write( "1-(1/k)^2 = 0.75 \n" ); document.write( "--- \n" ); document.write( "k = 2 \n" ); document.write( "---- \n" ); document.write( "So, u + 2s = 76.6 \n" ); document.write( "And u - 2s = 19.4 \n" ); document.write( "----- \n" ); document.write( "Subtract to get: \n" ); document.write( "4s = 57.2 \n" ); document.write( "s = 14.3 (that is the standard deviation) \n" ); document.write( "------ \n" ); document.write( "Solve for \"u\": \n" ); document.write( "u + 2*14.3 = 76.6 \n" ); document.write( "u = 76.6 - 28.6 \n" ); document.write( "u = 48 (that is the mean) \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |