document.write( "Question 653926: A chemist needs 160 milliliters of a 36% solution but has only 24% and 72% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.
\n" ); document.write( " A) 40 ml of 24%; 120 ml of 72%
\n" ); document.write( " B) 123 ml of 24%; 40 ml of 72%
\n" ); document.write( " C) 120 ml of 24%; 40 ml of 72%
\n" ); document.write( " D) 123 ml of 24%; 37 ml of 72% \n" ); document.write( "
Algebra.Com's Answer #408564 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A chemist needs 160 milliliters of a 36% solution but has only 24% and 72%
\n" ); document.write( " solutions available.
\n" ); document.write( " Find how many milliliters of each that should be mixed to get the desired solution.
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 72% solution required
\n" ); document.write( "The resulting amt is to be 16 ml, therefore
\n" ); document.write( "(160-x) = amt of 24% solution
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation using the decimal equiv of per cent
\n" ); document.write( ":
\n" ); document.write( ".72x + .24(160-x) = .36(160)
\n" ); document.write( ".72x + 38.4 - .24x = 57.6
\n" ); document.write( ".72x - .24x = 57.6 - 38.4
\n" ); document.write( ".48x = 19.2
\n" ); document.write( "x = 19.2/.48
\n" ); document.write( "x = 40 ml of 72% solution required
\n" ); document.write( ":
\n" ); document.write( "I'll let you find the amt of 24% required \n" ); document.write( "
\n" );