document.write( "Question 653878: Andrew can paint the neighbors house 5 times as fast as Bailey. The year Andrew and Bailey worked together, it took them 9 days. How long would it take each to paint the house? \r
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\n" ); document.write( "\n" ); document.write( "Andrew: 10 4/5
\n" ); document.write( "Bailey 54 days
\n" ); document.write( "But how?\r
\n" ); document.write( "\n" ); document.write( "If I read this right my formula should be:
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\n" ); document.write( "Andrew 1/x 9 9 1/x\r
\n" ); document.write( "\n" ); document.write( "Baily 1/5x 9 9 1/5x\r
\n" ); document.write( "\n" ); document.write( "9/x+1/5x=1 \r
\n" ); document.write( "\n" ); document.write( "Now I’m lost LCD should be x+5X?
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Algebra.Com's Answer #408531 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Try this thought process.\r
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\n" ); document.write( "\n" ); document.write( "If it takes A days to paint the house, then A can paint of the house in 1 day.\r
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\n" ); document.write( "\n" ); document.write( "If it takes B five times as long, then it takes B days, so he can paint of the house in 1 day.\r
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\n" ); document.write( "\n" ); document.write( "Since working together they can paint the whole house in 9 days, together they can paint of the house in one day.\r
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\n" ); document.write( "\n" ); document.write( "Putting that all together, A's th of a house plus B's th of a house must add up to their together th of a house:\r
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\n" ); document.write( "\n" ); document.write( "The LCD on the right needs one factor of and one factor of 5, so it is simply \r
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\n" ); document.write( "\n" ); document.write( "Hence\r
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\n" ); document.write( "\n" ); document.write( "Cross-multiply:\r
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\n" ); document.write( "\n" ); document.write( "So you know right off that B needs 54 days, and then A needs 54 divided by 5 or 10.8 which is .\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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