document.write( "Question 653779: The dimensions around a basketball court is 196 feet. If the length of the court is 8 feet more than twice the width, find the dimensions of the court. \n" ); document.write( "
Algebra.Com's Answer #408502 by checkley79(3341)\"\" \"About 
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PERIMETER =2L+2W
\n" ); document.write( "L=2W+8
\n" ); document.write( "196=2(2W+8)+2W
\n" ); document.write( "196=4W+16+2W
\n" ); document.write( "196=6W+16
\n" ); document.write( "6W=196-16
\n" ); document.write( "6W=180
\n" ); document.write( "W=180/6
\n" ); document.write( "W=30 FT WIDE FOR THE WIDTH.
\n" ); document.write( "L=2*30+8
\n" ); document.write( "L=60+8
\n" ); document.write( "L=68 FT. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "196=2*68+2*30
\n" ); document.write( "196=136+60
\n" ); document.write( "196=196
\n" ); document.write( "
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