document.write( "Question 653779: The dimensions around a basketball court is 196 feet. If the length of the court is 8 feet more than twice the width, find the dimensions of the court. \n" ); document.write( "
Algebra.Com's Answer #408502 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! PERIMETER =2L+2W \n" ); document.write( "L=2W+8 \n" ); document.write( "196=2(2W+8)+2W \n" ); document.write( "196=4W+16+2W \n" ); document.write( "196=6W+16 \n" ); document.write( "6W=196-16 \n" ); document.write( "6W=180 \n" ); document.write( "W=180/6 \n" ); document.write( "W=30 FT WIDE FOR THE WIDTH. \n" ); document.write( "L=2*30+8 \n" ); document.write( "L=60+8 \n" ); document.write( "L=68 FT. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "196=2*68+2*30 \n" ); document.write( "196=136+60 \n" ); document.write( "196=196 \n" ); document.write( " |