document.write( "Question 59579: Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height. \n" ); document.write( "
Algebra.Com's Answer #40847 by stanbon(75887)\"\" \"About 
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Find the dimensions of a box whose area is 196 cu. in., whose surface area is 280 sq. in., and whose width is twice its height.
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\n" ); document.write( "Let height be \"x\"
\n" ); document.write( "Width = \"2x\"
\n" ); document.write( "Base and top have area (2x)^2 = 4x^2
\n" ); document.write( "Sides have area (2x)x=2x^2
\n" ); document.write( "Total area = top + bottom + 4(side)
\n" ); document.write( "=4x^2 + 4x^2+4(2x^2)
\n" ); document.write( "=16x^2
\n" ); document.write( "So, 16x^2=280 sq. in.
\n" ); document.write( "x^2=17.5
\n" ); document.write( "x=4.1833 inch
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\n" ); document.write( "Checking:
\n" ); document.write( "Volumn = area of base * height
\n" ); document.write( "196 = (4x^2)(x)
\n" ); document.write( "49=x^3
\n" ); document.write( "x=3.659
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\n" ); document.write( "Comment: Something is wrong in Denmark
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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