document.write( "Question 653649: This is the problem: How many ounces of 50% antifreeze solution must be mixed with 10oz of an 80% antifreeze solution to produce a 60% antifreeze solution.\r
\n" ); document.write( "\n" ); document.write( "I'm supposed to make an equation for it and solve and I have no idea how to do so.
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Algebra.Com's Answer #408457 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = oz of 50% antifreeze solution needed
\n" ); document.write( "\"+.5x+\" = oz of antifreeze in 50% antifreeze solution
\n" ); document.write( "\"+.8%2A10+=+8+\" oz of antifreeze in 80% antifreeze solution
\n" ); document.write( "-------------
\n" ); document.write( "\"+%28+.5x+%2B+8+%29+%2F+%28+x+%2B+10+%29+=+.6+\"
\n" ); document.write( "\"+.5x+%2B+8+=+.6%2A%28+x+%2B+10+%29+\"
\n" ); document.write( "\"+.5x+%2B+8+=+.6x+%2B+6+\"
\n" ); document.write( "\"+.1x+=+2+\"
\n" ); document.write( "\"+x+=+20+\"
\n" ); document.write( "20 oz of 50% antifreeze solution is needed
\n" ); document.write( "check answer:
\n" ); document.write( "\"+%28+.5%2A20+%2B+8+%29+%2F+%28+20+%2B+10+%29+=+.6+\"
\n" ); document.write( "\"+%28+10+%2B+8+%29+%2F+30+=+.6+\"
\n" ); document.write( "\"+18%2F30+=+.6+\"
\n" ); document.write( "\"+18+=+.6%2A30+\"
\n" ); document.write( "\"+18+=+18+\"
\n" ); document.write( "OK\r
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