document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=653450>Question 653450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please i need help doing this step by step. The question asks me to solve the following equation in terms of \"y\"\r<BR>\n" );
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document.write( "R(x+y)=xy<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408420 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the following equation in terms of \"y\"<BR>\n" );
document.write( "R(x+y) = xy<BR>\n" );
document.write( "multiply what's inside the brackets<BR>\n" );
document.write( "Rx + Ry = xy<BR>\n" );
document.write( "Subtract Rx from both sides, subtract xy from both sides and you have:<BR>\n" );
document.write( "Ry - xy = -Rx<BR>\n" );
document.write( "Factor out y<BR>\n" );
document.write( "y(R-x) = -Rx<BR>\n" );
document.write( "Divide both sides by (R-x)<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-%28Rx%29%2F%28%28R-x%29%29 ALIGN=MIDDLE  ALT=\"-%28Rx%29%2F%28%28R-x%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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