document.write( "Question 653377: Question: In how many ways can a group of 2 boys and 3 girls be made out of a total of 6 boys and 4 girls? \r
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document.write( "Attempt: I started off by looking at the boys seperately, so 6 boys, two spots in the group should be 6P5= 30. Same thing for girls, 4P3=24. My final step was multiplying them together, 30x24 to achieve 720, operating on the principle of fundamental counting. However, I was told this answer of 720 was incorrect. \r
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document.write( "Would someone please show me how to do this question? \n" );
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Algebra.Com's Answer #408373 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I don't know where you got the idea that you needed to use permutations -- If the two boys are Bobby and Billy that would be the same as if they were Billy and Bobby, right?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need the number of combinations of 6 boys taken 2 (NOT 5) at a time times the number of combinations of 4 girls taken 3 at a time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |