document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=653336>Question 653336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate each expression:\r<BR>\n" );
document.write( "\n" );
document.write( "1.(3-7) to the second power=(-10)to the second power =100\r<BR>\n" );
document.write( "\n" );
document.write( "2. -6 to the second power - 3 to the thried power = -36-9=-45\r<BR>\n" );
document.write( "\n" );
document.write( "3. 6+10/2= 8\r<BR>\n" );
document.write( "\n" );
document.write( "4. -8/4 * 2=-4\r<BR>\n" );
document.write( "\n" );
document.write( "Are these correct? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408346 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.(3-7) to the second power=(-10)to the second power =100<BR>\n" );
document.write( "(-4)^2 = 16 <BR>\n" );
document.write( "(-10)^2 = 100<BR>\n" );
document.write( "------------------------- <BR>\n" );
document.write( "2. -6 to the second power - 3 to the thried power = -36-9=-45<BR>\n" );
document.write( "-6^2 -3^3 = -36 - 27 = -63<BR>\n" );
document.write( "------------------------------ <BR>\n" );
document.write( "3. 6+10/2= 8<BR>\n" );
document.write( "6 + 5 = 11<BR>\n" );
document.write( "============== <BR>\n" );
document.write( "4. -8/4 * 2=-4 <BR>\n" );
document.write( "-2*2 = -4<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );