document.write( "Question 653285: The height of a box is 5 inches. The length is three inches more than the width. Find the width if the volume is 350. \n" ); document.write( "
Algebra.Com's Answer #408318 by shweta(56)\"\" \"About 
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The box is a cuboid
\n" ); document.write( "height,h=5 inches, width=w and length,l=w+3 inches
\n" ); document.write( "Volume = 350
\n" ); document.write( "Volume =l*w*h
\n" ); document.write( " =(w+3)*w*5
\n" ); document.write( " =5w(w+3)
\n" ); document.write( " =5(w^2+ 3w)
\n" ); document.write( " 350 = 5w^2 +15w
\n" ); document.write( " 5w^2 +15w -350=0
\n" ); document.write( "Divide the equation by the H.C.F,5
\n" ); document.write( " w^2 + 3w -70=0
\n" ); document.write( " factors of 70= 2,5,7
\n" ); document.write( " w^2 + 10w -7w -70=0
\n" ); document.write( " w(w+10) -7(w+10)=0
\n" ); document.write( " (w+10)(w-7)=0
\n" ); document.write( " w=7,-10
\n" ); document.write( "the width of the cuboid cannot be negative ,so width is 7 inches and
\n" ); document.write( "length=w+3
\n" ); document.write( " l=7+3=10 inches
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