document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=653234>Question 653234</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 3% salt solution is mixed with a 9% salt solution. how many grams of the 9% salt solution were used to make 150 g of a 4% salt solution?<BR>\n" );
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document.write( "I don't know where to start in order to solve this. There will be 2 questions like this on my test on Thursday and I have a lot of trouble figuring out how to solve these. Do you have any tips or tricks for how to get equations out of word problems? It is very confusing for me, and my teacher isn't very good at explaining anything. :/ Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408316 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a 3% salt solution is mixed with a 9% salt solution. how many grams of the 9% salt solution were used to make 150 g of a 4% salt solution?\r<BR>\n" );
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document.write( "Let amount of the 9% salt to be mixed be T<BR>\n" );
document.write( "Since 150 g is to be made, then amount of 3% salt to be mixed = 150 – T\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Amount of 9% salt, plus amount of 3% salt equals 150 g of a 4% mixture, OR<BR>\n" );
document.write( ".09(T) + .03(150 – T) = .04(150)<BR>\n" );
document.write( ".09T + 4.5 - .03T = 6<BR>\n" );
document.write( ".09T - .03T = 6 – 4.5 <BR>\n" );
document.write( ".06T = 1.5\r<BR>\n" );
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document.write( "T, or amount of 9% salt to be mixed = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281.5%29%2F.06 ALIGN=MIDDLE  ALT=\"%281.5%29%2F.06\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2825%29 ALIGN=MIDDLE  ALT=\"highlight_green%2825%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > g\r<BR>\n" );
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document.write( "Not needed:<BR>\n" );
document.write( "Since total mixture is 150 g, then amount of 3% salt to be mixed = 150 – 25, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28125%29 ALIGN=MIDDLE  ALT=\"highlight_green%28125%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > g \r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com </SPAN>\n" );
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