document.write( "Question 653275: Before the final exam, a student has test scores of 72,83,65,73, and 62. If the final exam counts as one-third of the final grade, what score must the student receive in order to have a final average of 76? \n" ); document.write( "

Algebra.Com's Answer #408313 by Shana-D77(132) $\"\"$ $\"About$

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Great question! Though the student should aim higher than a 76% :)\r
\n" ); document.write( "\n" ); document.write( "If his average on the final exam counts for 1/3 of his overall grade, then the average of all the test scores he's already taken will count as 2/3 of his grade. \"of\" in math means to multiply. So:\r
\n" ); document.write( "\n" ); document.write( "Let's first find his test average:\r
\n" ); document.write( "\n" ); document.write( "(72+83+65+73+62)/5 = 71\r
\n" ); document.write( "\n" ); document.write( "His test averaage has been a 71.\r
\n" ); document.write( "\n" ); document.write( "So, 2/3 of 71 = (2/3)(71) = 47.33\r
\n" ); document.write( "\n" ); document.write( "Now set up the problem:\r
\n" ); document.write( "\n" ); document.write( "47.33 + (1/3)(x) = 76 (x stands for his grade on the final)\r
\n" ); document.write( "\n" ); document.write( "(1/3)(x) = 28.66 (subtracted 47.33 from both sides)
\n" ); document.write( "x = 86 (multiplied both sides by 3 to get rid of 1/3\r
\n" ); document.write( "\n" ); document.write( "He needs an 86% on the final. \n" ); document.write( "

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