document.write( "Question 59574: Please help me with this problem. Solve for x:\r
\n" ); document.write( "\n" ); document.write( "5 - 3│2x - 1| = -x .\r
\n" ); document.write( "\n" ); document.write( "Thank you,\r
\n" ); document.write( "\n" ); document.write( "welljesse \n" ); document.write( "
Algebra.Com's Answer #40830 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Please help me with this problem. Solve for x:
\n" ); document.write( "5 - 3│2x - 1| = -x .
\n" ); document.write( "CASE 1.......2X-1>0....THAT IS 2X>1...X>1/2
\n" ); document.write( "|2X-1|=2X-1
\n" ); document.write( "5-3(2X-1)=-X
\n" ); document.write( "5-6X+3=-X
\n" ); document.write( "5X=8
\n" ); document.write( "X=8/5...THIS SATISFIES THE ASSUMPTION AT THE BEGINING THAT X>1/2
\n" ); document.write( "HENCE ONE SOLUTION IS X = 8/5
\n" ); document.write( "CASE 2......2X-1<0....THAT IS 2X<1...X<1/2
\n" ); document.write( "|2X-1|=-(2X-1)=-2X+1
\n" ); document.write( "5-3(-2X+1)=-X
\n" ); document.write( "5+6X-3=-X
\n" ); document.write( "7X=-2
\n" ); document.write( "X=-2/7.....THIS SATISFIES THE ASSUMPTION AT THE BEGINING THAT X<1/2
\n" ); document.write( "HENCE SECOND SOLUTION IS X = -2/7\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "welljesse
\n" ); document.write( " \n" ); document.write( "
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