document.write( "Question 653158: evaluate the following expression when a=2 and b=-1\r
\n" ); document.write( "\n" ); document.write( "1.(2a-3b)to the 2nd power\r
\n" ); document.write( "\n" ); document.write( "2. 1/10y to the 2nd power + 3/2y to the 2nd power - 1/5y to the 2nd power = \n" ); document.write( "
Algebra.Com's Answer #408281 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
evaluate the following expression when \"a=2\" and \"b=-1\"\r
\n" ); document.write( "\n" ); document.write( "1.
\n" ); document.write( "\"%282a-3b%29%5E2=%282%2A2-3%28-1%29%29%5E2=%284%2B3%29%5E2=7%5E2=49\"\r
\n" ); document.write( "\n" ); document.write( "2. \r
\n" ); document.write( "\n" ); document.write( "in case you have this:\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\"0=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "but,in case you have this:\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "\"0=0\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );