document.write( "Question 653163: please help me with this. the complement of angle a is 20 less then half the supplement of angle a. find measurment of angle a
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #408277 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
ANGLE A=X
\n" ); document.write( "ANGLE B=X/2-20
\n" ); document.write( "A+B=90
\n" ); document.write( "X+(X/2-20)=90
\n" ); document.write( "X+X/2-20=90
\n" ); document.write( "(2X+X)/2=90+20
\n" ); document.write( "3X/2=110
\n" ); document.write( "3X=2*110
\n" ); document.write( "3X=220
\n" ); document.write( "X=220/3
\n" ); document.write( "X=73.33 ANS. FOR THE LARGER ANGLE.
\n" ); document.write( "73.33+73.33/2-20=90
\n" ); document.write( "73.33+36.67-20=90
\n" ); document.write( "73.33+16.67=90
\n" ); document.write( "90=90
\n" ); document.write( "
\n" ); document.write( "
\n" );