document.write( "Question 653117: S = n(a + l)/2 solve for l\r
\n" ); document.write( "\n" ); document.write( "The first thing I did was use distributive property for n(a + l). So then:\r
\n" ); document.write( "\n" ); document.write( "S = (na + nl)/2\r
\n" ); document.write( "\n" ); document.write( "Then, I thought about trying to cancel out the 2, leaving it as:\r
\n" ); document.write( "\n" ); document.write( "2S = 2na + 2nl\r
\n" ); document.write( "\n" ); document.write( "Am I on the right track? \n" ); document.write( "

Algebra.Com's Answer #408250 by Edwin McCravy(20056) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "That \"l\" looks too much like the number \"1\", so I'm going to \r\n" );
document.write( "use capital letters instead:\r\n" );
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document.write( "S = N(A + L)/2\r\n" );
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document.write( "Clear of fractions by multiplying both sides by 2\r\n" );
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document.write( "2S = 2N(A + L)/2\r\n" );
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document.write( "Then the 2's cancel on the right\r\n" );
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document.write( "2S = 2N(A + L)/2\r\n" );
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document.write( "and then we don't have any fractions:\r\n" );
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document.write( "2S = N(A + L)\r\n" );
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document.write( "Now remove the parentheses using the distributive principle:\r\n" );
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document.write( "2S = NA + NL\r\n" );
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document.write( "Now isolate the only term that contains L on the right by\r\n" );
document.write( "subtracting NA from both sides:\r\n" );
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document.write( "2S - NA = NL\r\n" );
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document.write( "Finally we divide both sides by N which is the coefficient of L:\r\n" );
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document.write( " = L\r\n" );
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document.write( "And if you like you can turn the equation around and write it as\r\n" );
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document.write( "L =  \r\n" );
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document.write( "Edwin

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