document.write( "Question 653038: Suppose five items are selected randomly from a production line that is known to produce defective items 5% of the time. What is the probability of getting exactly two defective items? \n" ); document.write( "
Algebra.Com's Answer #408217 by Shana-D77(132)\"\" \"About 
You can put this solution on YOUR website!
Thankfully not 25%!\r
\n" ); document.write( "\n" ); document.write( "5% = 0.05\r
\n" ); document.write( "\n" ); document.write( "The P of getting one defect is 0.05 (1/20)
\n" ); document.write( "The P of getting one defect is 0.05 (1/20)
\n" ); document.write( "I wrote this twice because the second deflect doesn't depend on the first one, like flipping a coin.\r
\n" ); document.write( "\n" ); document.write( "The P of getting two defects is (1/20)(1/20) = 1/400 = .25%\r
\n" ); document.write( "\n" ); document.write( "Though (you'll hate me here) the fact that you already pulled one defect affects the P of getting another. It makes the second chance less. How much less will depend on how many items are on the line: If there are 100 items vs if there are 1,000 items, for example. \r
\n" ); document.write( "\n" ); document.write( "If there are only 100, the chance of getting 2 is:
\n" ); document.write( "(5/100)(4/99) = .202%\r
\n" ); document.write( "\n" ); document.write( "If there are 1,000, the chance of getting 2 is:
\n" ); document.write( "(50/1000)(49/999) = .245%\r
\n" ); document.write( "\n" ); document.write( "Since you have no information on how many objects are being produced in the factory, I'd go with .25%
\n" ); document.write( ":) \n" ); document.write( "
\n" );