document.write( "Question 653001: A locomotive travels on a straight track at a constant speed of 40 mi/h, then reverses direction and returns to its starting point, traveling at a constant speed of 60 mi/h.
\n" ); document.write( "What is the average velocity for the round-trip?
\n" ); document.write( "What is the average speed for the round-trip?
\n" ); document.write( "What is the total distance traveled by the train if the total trip took 5 h?\r
\n" ); document.write( "\n" ); document.write( "I have no idea where to even begin...
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Algebra.Com's Answer #408200 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let the direction of travel for the initial leg of the trip be . Then the direction of travel for the return leg is . The vector sum of the two opposing vectors is the difference of the magnitudes in the direction of the greater magnitude, i.e. 20 mph @ .\r
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\n" ); document.write( "\n" ); document.write( "The average speed is the total distance traveled divided by the total travel time. The time for the outward leg is:\r
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\n" ); document.write( "\n" ); document.write( "hours.\r
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\n" ); document.write( "\n" ); document.write( "Where the one-way distance is \r
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\n" ); document.write( "\n" ); document.write( "The time for the return leg is:\r
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\n" ); document.write( "\n" ); document.write( "hours.\r
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\n" ); document.write( "\n" ); document.write( "The sum of these times is the total travel time:\r
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\n" ); document.write( "\n" ); document.write( "hours.\r
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\n" ); document.write( "\n" ); document.write( "The total distance travelled is , so the average speed is:\r
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\n" ); document.write( "\n" ); document.write( "mph.\r
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\n" ); document.write( "\n" ); document.write( "If the trip took 5 hours...\r
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\n" ); document.write( "\n" ); document.write( "If you go 48 mph for 5 hours, how far did you go?\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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