document.write( "Question 652950: Please help me with this proof
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document.write( "Given: <1 and<2 are supplementary, and <3 and<4 are supplementary
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document.write( "<2 is congruent to <3
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document.write( "Prove: <1 is congruent to <4
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document.write( "There are seven steps to this problem ! \n" );
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Algebra.Com's Answer #408174 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the measures of 1 and 2 is 180 by definition of supplementary\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the measures of 3 and 4 is 180 by definition of supplementary\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The measure of 2 equals the measure of 3 by definition of congruence\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of 1 and 3 is 180 by substitution equality\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 plus 3 equals 3 plus 4 by transitive equality\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 equals 4 by subtraction equality\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 congruent to 4 by definition of congruence\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |