document.write( "Question 652889: It takes Joan 4 times longet than jane to file the reports. Together, they can file reports in 24 minutes. How long would it take each woman to file the reports by herself?\r
\n" ); document.write( "\n" ); document.write( "It take Jane ___ minutes\r
\n" ); document.write( "\n" ); document.write( "It takes Joan ___ minutes
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Algebra.Com's Answer #408161 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
let \"x\" be the time\r
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\n" ); document.write( "\n" ); document.write( "If Jane do all work alone in \"x\" minutes, then in \"1\" minute she can do \"1%2Fx\" part of work\r
\n" ); document.write( "\n" ); document.write( "It takes Joan \"4+\"times longer than Jane to file reports, so Joan can do all work alone in \"4x\" minutes, then in \"1\" minute she can do \"1%2F%284x%29\" part of work\r
\n" ); document.write( "\n" ); document.write( "If they work together \"24\" minutes, then Jane does \"24%2Fx\"part of work, Joan does \"24%2F%284x%29=6%2Fx\"part of work. \r
\n" ); document.write( "\n" ); document.write( "In \"24\" minutes they did all work, all work is \"1\".\r
\n" ); document.write( "\n" ); document.write( "Equation\r
\n" ); document.write( "\n" ); document.write( "\"24%2Fx%2B6%2Fx=1\" Multiply both sides by \"x\"
\n" ); document.write( "\"24%2B6=x\"
\n" ); document.write( "\"x=30\"\r
\n" ); document.write( "\n" ); document.write( "So Jane needs \"30\" minutes for all work, Joan needs \"4%2A30=120\" minutes\r
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