document.write( "Question 59345: The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field. \n" ); document.write( "
Algebra.Com's Answer #40814 by pvaka(23)![]() ![]() ![]() You can put this solution on YOUR website! P=2L+2W \n" ); document.write( "L=x,W=y \n" ); document.write( "x=2y-5, P=230 \n" ); document.write( "-------------------------------------- \n" ); document.write( "2x+2y=230,x=2y-5>>(Substitute 2y-5 for x) \n" ); document.write( "2(2y-5)+2y=230 \n" ); document.write( "4y-10+2y=230 \n" ); document.write( "6y-10+10=230+10 \n" ); document.write( "6y=240 \n" ); document.write( "6y/6=240/6 \n" ); document.write( "y=40 \n" ); document.write( "x=2y-5 \n" ); document.write( "x=2(40)-5 \n" ); document.write( "x=80-5 \n" ); document.write( "x=75 \n" ); document.write( "Length=75 feet,width=40 ft\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |