document.write( "Question 652581: If the range of the function
\n" ); document.write( "y=(1/5)x+1
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\n" ); document.write( " C. {-11, 14, 29}
\n" ); document.write( " D. {-15, 10, 25} \n" ); document.write( "

Algebra.Com's Answer #408024 by Edwin McCravy(20054) $\"\"$ $\"About$

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document.write( "y=(1/5)x+1\r\n" );
document.write( "The range is {-2, 3, 6}, \r\n" );
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document.write( "Substitute y=-2 in\r\n" );
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document.write( "y=(1/5)x+1\r\n" );
document.write( "-2=(1/5)x+1\r\n" );
document.write( "Multiply both sides by 5 to clear of fractions:\r\n" );
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document.write( "-10=x+5\r\n" );
document.write( "-15=x\r\n" );
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document.write( "So -15 is in the domain.  This rules out A and C\r\n" );
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document.write( "Substitute y=3 in\r\n" );
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document.write( "y=(1/5)x+1\r\n" );
document.write( "3=(1/5)x+1\r\n" );
document.write( "Multiply both sides by 5 to clear of fractions:\r\n" );
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document.write( "15=x+5\r\n" );
document.write( "10=x  so 10 must be in the domain, so it's still either B or D\r\n" );
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document.write( "Substitute y=6 in\r\n" );
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document.write( "y=(1/5)x+1\r\n" );
document.write( "6=(1/5)x+1\r\n" );
document.write( "Multiply both sides by 5 to clear of fractions:\r\n" );
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document.write( "30=x+5\r\n" );
document.write( "25=x\r\n" );
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document.write( "So 25 must be in the domain.\r\n" );
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document.write( "Answer: D. {-15, 10, 25} \r\n" );
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document.write( "Edwin

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