document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652547>Question 652547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Perimeter of a rectangle is 46 ft. The width is 3ft less than twice the lenth. Find the lenth and width of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408008 by </B><A HREF=/tutors/aboutme.mpl?userid=mralgebra><B>mralgebra(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mralgebra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Perimeter of a rectangle is 46 ft. The width is 3ft less than twice the length. Find the length and width of the rectangle.\r<BR>\n" );
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document.write( "With problems like this, you'll just want to set up basic equations that use the information you're given in a pretty basic way.\r<BR>\n" );
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document.write( "\"The Perimeter of a rectangle is 46 ft.\"\r<BR>\n" );
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document.write( "If we call our length L and our width W, then we know this means that:\r<BR>\n" );
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document.write( "2L + 2W = 46\r<BR>\n" );
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document.write( "\"The width is 3ft less than twice the length.\"\r<BR>\n" );
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document.write( "Again, with the length L and width W:\r<BR>\n" );
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document.write( "W = 2L - 3\r<BR>\n" );
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document.write( "Now we have a simple system of two equations.\r<BR>\n" );
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document.write( "2L + 2W = 46<BR>\n" );
document.write( "W = 2L - 3\r<BR>\n" );
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document.write( "Let's substitute in 2L-3 for W in the first equation:\r<BR>\n" );
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document.write( "2L + 2W = 46<BR>\n" );
document.write( "2L + 2(2L - 3) = 46\r<BR>\n" );
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document.write( "From here, we'll simplify the equation to find the length L.\r<BR>\n" );
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document.write( "2L + 2(2L - 3) = 46<BR>\n" );
document.write( "2L + 4L - 6 = 46<BR>\n" );
document.write( "6L - 6 = 46<BR>\n" );
document.write( "6L - 6 + 6 = 46 + 6<BR>\n" );
document.write( "6L = 52<BR>\n" );
document.write( "L = 52/6 = 26/3\r<BR>\n" );
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document.write( "Since we know L, we can substitute it back into one of the equations to get W.\r<BR>\n" );
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document.write( "W = 2L - 3<BR>\n" );
document.write( "W = 2(26/3) - 3<BR>\n" );
document.write( "W = 52/3 - 3\r<BR>\n" );
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document.write( "We need a common denominator to do the subtraction.\r<BR>\n" );
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document.write( "W = 52/3 - 9/3<BR>\n" );
document.write( "W = 43/3\r<BR>\n" );
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document.write( "So our final answer is that the length is 26/3 ft and the width is 43/3 ft. </SPAN>\n" );
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