document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652531>Question 652531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular room is 6 feet longer than twice the width. If the room's perimeter is 152 feet, what are the rooms dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #408006 by </B><A HREF=/tutors/aboutme.mpl?userid=Shana-D77><B>Shana-D77(132)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shana-D77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shana-D77><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=408006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, so let's start by translating this problem literally:\r<BR>\n" );
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document.write( "\"The length of a rectangular room is 6 feet longer than twice the width\"<BR>\n" );
document.write( "L =  2w  + 6  (remember \"=\" reads as \"is\")\r<BR>\n" );
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document.write( "\"If the Perimeter is 152 feet\"<BR>\n" );
document.write( "P = 152\r<BR>\n" );
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document.write( "We know that the perimeter of a rectangle is L + L + W + W or 2L + 2W\r<BR>\n" );
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document.write( "So, we have 152 = 2L + 2W\r<BR>\n" );
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document.write( "Our two equations are then:<BR>\n" );
document.write( "L = 2w + 6<BR>\n" );
document.write( "2L + 2w = 152\r<BR>\n" );
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document.write( "Since the first equation is solved for L, let's get the second equation also solved for L:\r<BR>\n" );
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document.write( "2L + 2w = 152<BR>\n" );
document.write( "L + w = 76  (dided everything by 2)<BR>\n" );
document.write( "L = 76 - w  (subtracted w from both sides)\r<BR>\n" );
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document.write( "Now we have:<BR>\n" );
document.write( "L = 2w + 6<BR>\n" );
document.write( "L = 76 - w\r<BR>\n" );
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document.write( "Since they're both =L, they're equal to each other (transitive peoperty):\r<BR>\n" );
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document.write( "2w + 6 = 76 - w\r<BR>\n" );
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document.write( "3w + 6 = 76 (added w to both sides)\r<BR>\n" );
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document.write( "3w = 70 (subtracted 6 from both sides)\r<BR>\n" );
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document.write( "w = 70/3 or 23.333 feet (23 feet, 4 inches)\r<BR>\n" );
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document.write( "To find L, we can plug our w back into any of the equations we used.  The easiest may be the 152 = 2L + 2w equation:\r<BR>\n" );
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document.write( "152 = 2L + 2(70/3)<BR>\n" );
document.write( "152 = 2L + 140/3<BR>\n" );
document.write( "316/3 = 2L    (subtracted 140/3 from both sides)<BR>\n" );
document.write( "L = 158/3 (52.66 feet or 52 feet and 8 inches)\r<BR>\n" );
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document.write( "w = 23 feet, 4 inches<BR>\n" );
document.write( "L = 52 feet, 8 inches </SPAN>\n" );
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