document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652351>Question 652351</A>: <I><SPAN STYLE=\"word-break: break-all;\"> square root of -15 multiplied by square root of -3 divided by square root of 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407963 by </B><A HREF=/tutors/aboutme.mpl?userid=Shana-D77><B>Shana-D77(132)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shana-D77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shana-D77><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> square root of a negative, as you know, is not real.  BUT, if you multiply a negative square root by another negative square root, you get a positive!  So, \r<BR>\n" );
document.write( "\n" );
document.write( "(sqrt -15)(sqrt -3) = sqrt 45\r<BR>\n" );
document.write( "\n" );
document.write( "sqrt 45 simplifies to sqrt 9 * sqrt 5\r<BR>\n" );
document.write( "\n" );
document.write( "sqrt 9 = 3 so,\r<BR>\n" );
document.write( "\n" );
document.write( "sqrt 45 = 3 sqrt 5\r<BR>\n" );
document.write( "\n" );
document.write( "(3 sqrt 5)/(sqrt 5) = 3\r<BR>\n" );
document.write( "\n" );
document.write( "Answer = 3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );