document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59517>Question 59517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base angles of an isosceles triangle are congruent. If the measure of each of the base angles is twice the measure of the third angle, find the measure of all three angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40796 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the angle at the top equal x<BR>\n" );
document.write( "Then the other angles are 2x and 2x<BR>\n" );
document.write( "The sum of the angles of  a triangle is always 180 degrees<BR>\n" );
document.write( "x + 2x + 2x = 180<BR>\n" );
document.write( "5x = 180<BR>\n" );
document.write( "x = 36<BR>\n" );
document.write( "2x = 72<BR>\n" );
document.write( "2x = 72<BR>\n" );
document.write( "check<BR>\n" );
document.write( "36 + 72 + 72 = 180<BR>\n" );
document.write( "180 = 180<BR>\n" );
document.write( "OK </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );