document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652319>Question 652319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, Im having difficulty figuring out this question. I found a solution to this problem on this site, but I do not think it was solved in the correct manner (I could be wrong though). Thanks for your help!\r<BR>\n" );
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document.write( "The ratio of the weight of sodium to that of chlorine in common table salt is 5 to 3. Find the amount of each element in a salt compound weighing 200 pounds. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407954 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio of the weight of sodium to that of chlorine in common table salt is 5 to 3. Find the amount of each element in a salt compound weighing 200 pounds.<BR>\n" );
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document.write( "5 to 3 is the same as 5x to 3x where wt. of sodium is 5x.<BR>\n" );
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document.write( "5x + 3x = 200 lbs.<BR>\n" );
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document.write( "8x = 200<BR>\n" );
document.write( "x = 25<BR>\n" );
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document.write( "Wt of sodium = 5x = 5*25 = 125 lbs<BR>\n" );
document.write( "Wt of chlorine = 3x = 3*25 = 75 lbs<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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