document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652251>Question 652251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the domain of the function g(x)=x+7/x^2-36\r<BR>\n" );
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document.write( "Any help would be appreciated!\r<BR>\n" );
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document.write( "Thank you.\r<BR>\n" );
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document.write( "Rae Henson </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407944 by </B><A HREF=/tutors/aboutme.mpl?userid=Shana-D77><B>Shana-D77(132)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shana-D77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shana-D77><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407944\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Finding the domain\" is a fancy pants way of saying \"find where the denuminator is not zero\"\r<BR>\n" );
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document.write( "(x + 7)/(x^2 - 36) factors to:\r<BR>\n" );
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document.write( "(x + 7)/(x - 6)(x + 6)\r<BR>\n" );
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document.write( "If x = 6, the denominator would equal zero (6 - 6)(6 + 6) = (0)(12) = 0.  So, 6 is excluded.  Same for -6.\r<BR>\n" );
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document.write( "Domain is \"all Real numbers except 6 and -6\"\r<BR>\n" );
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document.write( "Now, if one of those (  ) in the denominator cancelled with the (x + 7) in the numerator, we could cancel that parenthesis and have only one exception to the domain.  Example: (x + 6)/(x + 6)(x - 6).  The (x + 6)s cancel so that the domain would be \"all Reals except 6 (only).\" </SPAN>\n" );
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