document.write( "Question 652262: x+2y=200
\n" ); document.write( "x=y+50 \n" ); document.write( "
Algebra.Com's Answer #407943 by Shana-D77(132)\"\" \"About 
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x+2y=200
\n" ); document.write( "x=y+50\r
\n" ); document.write( "\n" ); document.write( "if x + 2y = 200, then let's solve it for x... \r
\n" ); document.write( "\n" ); document.write( "x = 200 - 2y (subtracted 2y from both sides)\r
\n" ); document.write( "\n" ); document.write( "Now we have two \"x +\" equations\"\r
\n" ); document.write( "\n" ); document.write( "x = y + 50
\n" ); document.write( "x = 200 - 2y\r
\n" ); document.write( "\n" ); document.write( "If x equals two things, those two things equal each other (transitive property)\r
\n" ); document.write( "\n" ); document.write( "y + 50 = 200 - 2y\r
\n" ); document.write( "\n" ); document.write( "3y + 50 = 200 (added 2y to both sides)\r
\n" ); document.write( "\n" ); document.write( "3y = 150 (subtracted 50 from both sides)\r
\n" ); document.write( "\n" ); document.write( "y = 50.\r
\n" ); document.write( "\n" ); document.write( "if y = 50, sub 50 back in for y into either of the two original equations (how about both to check?)\r
\n" ); document.write( "\n" ); document.write( "x + 2(50) = 200
\n" ); document.write( "x + 100 = 200
\n" ); document.write( "x = 100\r
\n" ); document.write( "\n" ); document.write( "x = 50 + 50
\n" ); document.write( "x = 100\r
\n" ); document.write( "\n" ); document.write( "it's the same, so x = 100, y = 50
\n" ); document.write( "The lines cross at (100, 50)\r
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