document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652275>Question 652275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for y:<BR>\n" );
document.write( "5=3y-2x/3y<BR>\n" );
document.write( "Both the 3y and -2x are over 3y\r<BR>\n" );
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document.write( "Thanks!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407942 by </B><A HREF=/tutors/aboutme.mpl?userid=Shana-D77><B>Shana-D77(132)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shana-D77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shana-D77><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 = (3y - 2x)/3y\r<BR>\n" );
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document.write( "Always multiply both sides by the denominator to get rid of the horrible fraction.\r<BR>\n" );
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document.write( "15y = 3y - 2x\r<BR>\n" );
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document.write( "12y = -2x (subtracted 3y from both sides)\r<BR>\n" );
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document.write( "y = -2x/12 (divided both sides by 12)\r<BR>\n" );
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document.write( "y = -1x/6 (reduced)\r<BR>\n" );
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document.write( "y = -x /6 (cleaned up a bit)\r<BR>\n" );
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