document.write( "Question 652264: Roger's age is two times the age of his sister. Last year his age was three times the age of his sister. How old is Roger? \n" ); document.write( "
Algebra.Com's Answer #407940 by Shana-D77(132)![]() ![]() You can put this solution on YOUR website! This year, Roger is R and Sister is S \n" ); document.write( "Last year, Roger is R-1 and Sister is S-1\r \n" ); document.write( "\n" ); document.write( "TODAY: \n" ); document.write( "R = 2S\r \n" ); document.write( "\n" ); document.write( "LAST YEAR: \n" ); document.write( "R - 1 = 3(S - 1) \n" ); document.write( "R - 1 = 3S - 3\r \n" ); document.write( "\n" ); document.write( "Sub in 2S for R (because R = 2S)\r \n" ); document.write( "\n" ); document.write( "2S - 1 = 3s - 3\r \n" ); document.write( "\n" ); document.write( "S = 2. So sister is 2 this year, Roger is 4. \n" ); document.write( "Last year, Sister was 1 and Roger was \"three times her age\" or 3. \n" ); document.write( " |