document.write( "Question 652264: Roger's age is two times the age of his sister. Last year his age was three times the age of his sister. How old is Roger? \n" ); document.write( "
Algebra.Com's Answer #407940 by Shana-D77(132)\"\" \"About 
You can put this solution on YOUR website!
This year, Roger is R and Sister is S
\n" ); document.write( "Last year, Roger is R-1 and Sister is S-1\r
\n" ); document.write( "\n" ); document.write( "TODAY:
\n" ); document.write( "R = 2S\r
\n" ); document.write( "\n" ); document.write( "LAST YEAR:
\n" ); document.write( "R - 1 = 3(S - 1)
\n" ); document.write( "R - 1 = 3S - 3\r
\n" ); document.write( "\n" ); document.write( "Sub in 2S for R (because R = 2S)\r
\n" ); document.write( "\n" ); document.write( "2S - 1 = 3s - 3\r
\n" ); document.write( "\n" ); document.write( "S = 2. So sister is 2 this year, Roger is 4.
\n" ); document.write( "Last year, Sister was 1 and Roger was \"three times her age\" or 3.
\n" ); document.write( "
\n" );