document.write( "Question 652174: Factor the trinominal \r
\n" ); document.write( "\n" ); document.write( "y^4+9y^3+8y^2\r
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Algebra.Com's Answer #407922 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"y%5E4%2B9y%5E3%2B8y%5E2\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2%28y%5E2%2B9y%2B8%29\" Factor out the GCF \"y%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"y%5E2%2B9y%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"y%5E2%2B9y%2B8\", we can see that the first coefficient is \"1\", the second coefficient is \"9\", and the last term is \"8\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"8\" to get \"%281%29%288%29=8\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"8\" (the previous product) and add to the second coefficient \"9\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"8\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"8\":\r
\n" ); document.write( "\n" ); document.write( "1,2,4,8\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"8\".\r
\n" ); document.write( "\n" ); document.write( "1*8 = 8
\n" ); document.write( "2*4 = 8
\n" ); document.write( "(-1)*(-8) = 8
\n" ); document.write( "(-2)*(-4) = 8\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"9\":\r
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First NumberSecond NumberSum
181+8=9
242+4=6
-1-8-1+(-8)=-9
-2-4-2+(-4)=-6
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"1\" and \"8\" add to \"9\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"1\" and \"8\" both multiply to \"8\" and add to \"9\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"9y\" with \"y%2B8y\". Remember, \"1\" and \"8\" add to \"9\". So this shows us that \"y%2B8y=9y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2%2Bhighlight%28y%2B8y%29%2B8\" Replace the second term \"9y\" with \"y%2B8y\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%5E2%2By%29%2B%288y%2B8%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"y%28y%2B1%29%2B%288y%2B8%29\" Factor out the GCF \"y\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"y%28y%2B1%29%2B8%28y%2B1%29\" Factor out \"8\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B8%29%28y%2B1%29\" Combine like terms. Or factor out the common term \"y%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "So \"y%5E2%28y%5E2%2B9y%2B8%29\" then factors further to \"y%5E2%28y%2B8%29%28y%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"y%5E4%2B9y%5E3%2B8y%5E2\" completely factors to \"y%5E2%28y%2B8%29%28y%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"y%5E4%2B9y%5E3%2B8y%5E2=y%5E2%28y%2B8%29%28y%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"y%5E2%28y%2B8%29%28y%2B1%29\" to get \"y%5E4%2B9y%5E3%2B8y%5E2\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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