document.write( "Question 652123: what polygon has a number of sides that is five times the number of diagonals \n" ); document.write( "
Algebra.Com's Answer #407920 by KMST(5328)\"\" \"About 
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The way I understand geometry, the answer is \"highlight%28NONE%29\" .
\n" ); document.write( "I am betting there is a mix-up in the wording of the problem.
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\n" ); document.write( "The way I understand geometry,
\n" ); document.write( "a diagonal of a polygon is a segment that connects two vertices of the polygon, but is not a side of the polygon.
\n" ); document.write( "If a polygon has \"n\" sides, it will have n vertices.
\n" ); document.write( "Each vertex will be connected to \"2\" other vertices by sides,
\n" ); document.write( "and can be connected to the remaining \"n-3\" other vertices by a diagonal.
\n" ); document.write( "If we multiply the \"n-3\" diagonals coming out of each vertex times \"n\" , the number of vertices,
\n" ); document.write( "we get \"n%28n-3%29\" ,
\n" ); document.write( "but we are counting each diagonal twice.
\n" ); document.write( "The polygon with \"n\" sides has \"d=n%28n-3%29%2F2\" diagonals.
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\n" ); document.write( "To find what polygon has a number of sides that is five times the number of diagonals, we can set up an equation
\n" ); document.write( "\"n=5%2A%28n%28n-3%29%2F2%29\"
\n" ); document.write( "or we can make a table comparing \"n\" and \"d\" .\r
\n" ); document.write( "\n" ); document.write( "For that table:
\n" ); document.write( "A triangle has \"3\" sides and \"0\" diagonals.
\n" ); document.write( "A quadrilateral has \"4\" sides and \"2\" diagonals.
\n" ); document.write( "From then on, the number of sides is equal to or less than the number of diagonals.
\n" ); document.write( "A pentagon has \"5\" sides and \"5\" diagonals.
\n" ); document.write( "A hexagon has \"6\" sides and \"9\" diagonals.
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\n" ); document.write( "Either way (equation or table), the answer is \"highlight%28NONE%29\" .
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\n" ); document.write( "If we wanted to know what polygon has a number of diagonals that is five times the number of sides, our equation would be
\n" ); document.write( "\"5n=n%28n-3%29%2F2\"
\n" ); document.write( "\"5n=n%28n-3%29%2F2\" --> \"2%2A5n=2%2A%28n%28n-3%29%2F2%29\" --> \"10n=n%28n-3%29\" --> \"10n=n%5E2-3n%29\" --> \"10n%2B3n=n%5E2-3n%2B3n%29\" --> \"13n=n%5E2%29\"
\n" ); document.write( "Since \"n=0\" does not make a polygon, we know \"n\" is not \"0\" .
\n" ); document.write( "\"13n=n%5E2%29\" --> \"13n%2Fn=n%5E2%2Fn%29\" --> \"13=n%29\" or \"highlight%28n=13%29\" .
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