document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=652055>Question 652055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 3 feet less than five times its width. the perimeter is 66 feet. find the dimensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407896 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of Rectangle(P) equals 2*Length plus 2*Width or P=2L+2W<BR>\n" );
document.write( "Let W=width<BR>\n" );
document.write( "Then Length (L)=5W-3\r<BR>\n" );
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document.write( "Sooooo<BR>\n" );
document.write( "P=2*(5W-3)+2*W simplify<BR>\n" );
document.write( "66=10W-6+2W add 6 to both sides<BR>\n" );
document.write( "12W=72<BR>\n" );
document.write( "W=6ft----width of rectangle<BR>\n" );
document.write( "L=5*6-3=27 ft----length of rectangle\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "2*27+2*6=66<BR>\n" );
document.write( "54+12=66<BR>\n" );
document.write( "66=66\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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