document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59528>Question 59528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I thought I had the right answer but it came back as wrong.  Can someone please let me know how to work this?\r<BR>\n" );
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document.write( "1/square root 3 + square root 3\r<BR>\n" );
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document.write( "*I got 4/square root 3\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40788 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/square root 3 )+ square root 3 <BR>\n" );
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document.write( "(1/sqrt3)  + sqrt3<BR>\n" );
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document.write( "Create sqrt3 as the denominator of both fractions:<BR>\n" );
document.write( "(1/sqrt3) + (sqrt3)^2/sqrt3<BR>\n" );
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document.write( "Now add the numberators to get:<BR>\n" );
document.write( "(1+(sqrt3)^2)/sqrt3<BR>\n" );
document.write( "=(1+3)/sqrt3<BR>\n" );
document.write( "=4/sqrt3<BR>\n" );
document.write( "Comment: You have it right.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
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