document.write( "Question 652030: How would i write the equation of the line that is perpendicular to the graph of y=1/2x+6,and whose y-intercept is (0, -2). \n" ); document.write( "
Algebra.Com's Answer #407879 by nerdybill(7384)\"\" \"About 
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How would i write the equation of the line that is perpendicular to the graph of y=1/2x+6,and whose y-intercept is (0, -2).
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\n" ); document.write( "\"slope-intercept\" form is
\n" ); document.write( "y = mx+b
\n" ); document.write( "where
\n" ); document.write( "m is the slope
\n" ); document.write( "b is the y-intercept
\n" ); document.write( ".
\n" ); document.write( "slope of:
\n" ); document.write( "y=1/2x+6
\n" ); document.write( "is 1/2 (which is 'm' of our new line)
\n" ); document.write( ".
\n" ); document.write( "if y-intercept is (0, -2) then 'b' of our new line is -2
\n" ); document.write( ".
\n" ); document.write( "so,
\n" ); document.write( "y = mx+b
\n" ); document.write( "y = (1/2)x+(-2)
\n" ); document.write( "y = (1/2)x-2 (answer)\r
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