document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=651937>Question 651937</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two buses leave columbia, ohio at the same time and travel in the opposite direction one bus averages 55 mph and the other bus averages 48 mph when will they be 618 miles apart? I dont understand how to work this problem out  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #407863 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=407863\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two buses leave columbia, ohio at the same time and travel in the opposite direction one bus averages 55 mph and the other bus averages 48 mph when will they be 618 miles apart? I dont understand how to work this problem out<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x = distance 55 mph bus traveled<BR>\n" );
document.write( "618-x=distance 48 mph bus traveled<BR>\n" );
document.write( "travel time=distance/speed (same for both buses)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x/55=(618-x)/48<BR>\n" );
document.write( "48x=55(618-x)<BR>\n" );
document.write( "48x=33990-55x<BR>\n" );
document.write( "103x=33990<BR>\n" );
document.write( "x=330 mi<BR>\n" );
document.write( "travel time=330/55=6 hrs<BR>\n" );
document.write( "when will buses be 618 miles apart? 6 hrs </SPAN>\n" );
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